when running linux.bat

when running linux.bat

[Glenn Ervin]

when I run linux.bat, which really runs loadlin.exe, it asks for an image
file to run with options.
Is this where I type in one of the names for a speakup file?
which speakup file should I type in?  and is the options where I would type
in something about dectalk?


Sincerely,
O. Glenn Ervin-- (Lenny) N0YJV
Northeast Nebraska
gervin@kdsi.net
or My Work e-mail:
gervin@ncbvi.state.ne.us

Re: when running linux.bat

[Tony Baechler]

Hello.  My linux.bat was a single line, similar to the following.  If you 
are using umsdos, change accordingly, but I really do not recommend umsdos 
if you can avoid it.

c:\linux\loadlin vmlinuz root=/dev/hda9 ro speakup_synth=dectlk

Let us quickly look at the above.  Replace c:\linux with the real path to 
your Linux kernel.  Also, replace vmlinuz with the kernel name.  I had 
several different kernels available, so I had names like lnx2219 (for 
2.2.19), lnx2412 (for 2.4.12) etc.  Note that this method works with 
Slackware and Debian with no problems.  Finally, the root device is just 
that, the root of your Linux filesystem.  I used /dev/hda8 or /dev/hda9 
which were logical drives.  This way I could still boot to Windows but had 
an entrance into Linux as well.  Note that lilo breaks with this 
setup.  The "ro" means read-only for filesystem checking.  You pass Speakup 
parameters on the command line, so "dectlk" is the DEC Expres.  The 
"speakup_synth=" is a variable needed by the kernel for the Speakup 
synthesizer.  I hope that helps.

If you are interested, I also had my system set up so I could hold down "z" 
at boot to bypass the rest of the Windows boot and jump right into 
Linux.  It worked well.