Re: Telephone / Address directory program?

[<rmann@rmisp.net>]

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Hi.
I've attached a simple program to store People's addresses.  To compile
it, do "gcc -o address address.cpp".


On Wed, 16 Jan 2002, Raul A. Gallegos wrote:

> Georgina said the following on Wed, Jan 16, 2002 at 11:23:02PM +0000:
> > Hi
>
> Howdy.
>
> > I wondered if there were any handy terminal programs for storing telephone numbers and addresses.  While I've been playing with postgresql, I don't know variations of the select statements well enough for this simple task.  It feels like using a sledge hammer for a very small nut.  I'm just looking for a small program that I as a single user can enter names, addresses and telephone numbers and retrieve quite easily.  Any ideas?
>
>
> I don't remember which distro you use but there is a Debian package
> which I use and works quite well.  If you don't use Debian I'm sure you
> can find it from freshmeat.net and install it manually.
>
> Package: abook
> Priority: optional
> Section: mail
> Installed-Size: 176
> Maintainer: Alan Ford <alan@whirlnet.co.uk>
> Architecture: i386
> Version: 0.4.14-1
> Depends: libc6 (>= 2.2.3-7), libncurses5 (>= 5.2.20010310-1)
> Filename: pool/main/a/abook/abook_0.4.14-1_i386.deb
> Size: 34556
> MD5sum: 39683e77a3ad53bcd551865b82c5e7c5
> Description: A text-based ncurses address book application.
>  abook is a text-based ncurses address book application. It provides
> many
>  different fields of user info. abook is designed for use with mutt, but
>  can be used independently.
>
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#include <iostream.h>
#include <fstream.h>//header file for file IO
int main()
{
char name[30];
char address[30];
char city[30];
char state[3];
char zip[6];
char phone[13];
int cont = 1;
ofstream outfile;
outfile.open("address.txt", ios::app);
if(outfile)
{
while(cont != 0)
{
cout << "Enter the person's name.\n";
cin.get(name, 30);
cin.ignore(80, '\n');
cout << "Enter the person's address.\n";
cin.get(address, 30);
cin.ignore(80, '\n');
cout << "Enter the city.\n";
cin.get(city, 30);
cin.ignore(80, '\n');
cout << "Enter the two letter state abreviation.\n";
cin.get(state, 3);
cin.ignore(80, '\n');
cout << "Enter the postal code.\n";
cin.get(zip, 6);
cin.ignore(80, '\n');

cout << "Enter the phone number.\n";
cin.get(phone, 13);
cin.ignore(80, '\n');
outfile << name << "\n";
outfile << address << "\n";
outfile << city << "\n";
outfile << state << ",";
outfile << zip << "\n";
outfile << phone << "\n";
cout << "To quit this program type 0 then return.\n";
cout << "Type return to continue.\n";
cin >> cont;
}
}
else
{
	cout << "Their was an error opening the file.\n";
}
outfile.close();
return 0;
}