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Date: Thu, 28 Apr 2005 10:49:21 -0400
From: David Bruzos <david@bruzos.org>
To: "Speakup is a screen review system for Linux." <speakup@braille.uwo.ca>
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Subject: Re: Bash Problem
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Hi Janina:
Could it be that you are missing the declaration of the "$i" variable.  I added it and it worked for me.  This is what I 
got:

#!/bin/bash

for i in $(ls); do
	if [ "$i" != "incoming/" ]; then
		echo "$i"
	fi
done

It seems as if you are missing the "i" after the "for".

HTH

David B.

On Thu, Apr 28, 2005 at 10:03:25AM -0400, Janina Sajka wrote:
> I'm confused over some simple bash syntax. If I write the following at
> the bash (ver 3.0) prompt, all works as expected--no errors.
> 
> But, if I execute from a script file (which begins with a #!/bin/bash of
> course), I get:
> 
> 	line 4: syntax error near unexpected token `then'
> 
> What am I missing? All help much appreciated.
> 
> 
> for in $( ls); do
> if [ "$i" != "incoming/" ]; then
> echo $i
> fi
> done
> 
> 
> -- 
> 
> Janina Sajka				Phone: +1.202.494.7040
> Partner, Capital Accessibility LLC	http://www.CapitalAccessibility.Com
> 
> Chair, Accessibility Workgroup		Free Standards Group (FSG)
> janina@freestandards.org		http://a11y.org
> 
> If Linux can't solve your computing problem, you need a different problem.
> 
> 
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