From mboxrd@z Thu Jan 1 00:00:00 1970 Received: from fed1rmmtao03.cox.net ([68.230.241.36]) by speech.braille.uwo.ca with esmtp (Exim 3.36 #1 (Debian)) id 1DECKW-0008BK-00 for ; Wed, 23 Mar 2005 15:19:53 -0500 Received: from nedelko83f1172 ([68.228.49.78]) by fed1rmmtao03.cox.net (InterMail vM.6.01.04.00 201-2131-118-20041027) with SMTP id <20050323201906.XVRV1282.fed1rmmtao03.cox.net@nedelko83f1172> for ; Wed, 23 Mar 2005 15:19:06 -0500 Message-ID: <001201c52fe5$938dfee0$4e31e444@nedelko83f1172> From: "Ned" To: "Speakup is a screen review system for Linux." Date: Wed, 23 Mar 2005 13:19:11 -0700 MIME-Version: 1.0 X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 6.00.2900.2180 X-MIMEOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable X-Content-Filtered-By: Mailman/MimeDel 2.1.5 Subject: how to chek for the number of options in an app X-BeenThere: speakup@braille.uwo.ca X-Mailman-Version: 2.1.5 Precedence: list Reply-To: "Speakup is a screen review system for Linux." List-Id: "Speakup is a screen review system for Linux." List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Wed, 23 Mar 2005 20:19:53 -0000 Hi all, Is there a way to check, without counting by hand within the manual, how = many options are there for a command such as ls, more, bash, etc? If not, what's the shortest way of doing that through the man? Many thanks in advance! Ned