From mboxrd@z Thu Jan 1 00:00:00 1970 Received: from i216-58-12-178.avalonworks.net ([216.58.12.178] helo=interfree.ca) by speech.braille.uwo.ca with esmtp (Exim 3.36 #1 (Debian)) id 1D6fBt-0000Np-00 for ; Wed, 02 Mar 2005 20:31:49 -0500 Received: from gate ([192.168.1.1] helo=canadarm) by interfree.ca with esmtp (Exim 3.36 #1 (Debian)) id 1D6fBt-0000WP-00 for ; Wed, 02 Mar 2005 20:31:49 -0500 From: "Rejean Proulx" To: Date: Wed, 2 Mar 2005 20:35:59 -0500 Message-ID: <000001c51f91$5bf9e570$6a01a8c0@canadarm> MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 Subject: FW: Cron /usr/bin/php4 -q /usr/share/phpgroupware//phpgwapi/cron/asyncservices.php default X-BeenThere: speakup@braille.uwo.ca X-Mailman-Version: 2.1.5 Precedence: list Reply-To: "Speakup is a screen review system for Linux." List-Id: "Speakup is a screen review system for Linux." List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Thu, 03 Mar 2005 01:31:49 -0000 I am trying to remove phpgroupware from my Debian system as I don't use = it. When I remove it using apt-get remove phpgroupware every 5 minutes I get = the following mail. How do I remove what ever it is from cron? I can't = find what causes this. I thought that when you remove a package, it should remove that sort of configuration. -----Original Message----- From: CronDaemon [mailto:www-data@interfree.ca] On Behalf Of Cron Daemon Sent: Wednesday, March 02, 2005 8:20 PM To: www-data@interfree.ca Subject: Cron /usr/bin/php4 -q /usr/share/phpgroupware//phpgwapi/cron/asyncservices.php default Could not open input file: /usr/share/phpgroupware//phpgwapi/cron/asyncservices.php. __________ NOD32 1.1017 (20050302) Information __________ This message was checked by NOD32 antivirus system. http://www.nod32.com